-3x^2+196x+195=0

Solution for -3x^2+196x+195=0 equation:

-3x^2+196x+195=0

a = -3; b = 196; c = +195;
Δ = b2-4ac
Δ = 1962-4·(-3)·195
Δ = 40756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40756}=\sqrt{4*10189}=\sqrt{4}*\sqrt{10189}=2\sqrt{10189}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-2\sqrt{10189}}{2*-3}=\frac{-196-2\sqrt{10189}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+2\sqrt{10189}}{2*-3}=\frac{-196+2\sqrt{10189}}{-6}
$